Question

Km

Two buses leave a station at the same time and travel in opposite directions. One bus travels 10 - - slower than the other. If the two buses are 1442
kilometers apart after 7 hours, what is the rate of each bus?
Rate of the slower bus:
X
5
?
Rate of the faster bus:​

Answer 1

The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph .

Explanation:

Given as :

The two buses apart 1442 km

The time taken for apart = 7 hours

Let The speed of faster bus = x kmph

The speed of slower bus = ( x - 10 ) kmph

Now Speed =
`(\textrm distance)/(\textrm time)`

∵ Both the buses traveling in opposite direction

So, The speed of faster bus + the speed of slower bus =
`(\textrm distance cover)/(\textrm time)`

Or, x + x - 10 =
`(1442)/(7)`

or, 2 x = 206 + 10

or, 2 x = 216

∴ x =
`(216)/(2)`

I.e x = 108 kmph

So, The speed of faster bus = x = 108 kmph

And The speed of slower bus = ( x - 10 ) = 108 - 10 = 98 kmph

Hence The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph . Answer