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A 3.00-m rod is pivoted about its left end. A force of 7.80 N is applied perpendicular to the rod at a distance of 1.60 m from the pivot causing a ccw torque, and a force of 2.60 N is applied at the end of the rod 3.00 m from the pivot. The 2.60-N force is at an angle of 30.0o to the rod and causes a cw torque. What is the net torque about the pivot? (Take ccw as positive.)

a. 26.4 N·m

b. 4.68 N·m

c. 8.58 N·m

d. -8.58 N·m

e. -16.4 N·m

2 Answers

5 votes

Final answer:

The net torque about the pivot is calculated by finding the individual torques caused by each force and then subtracting the clockwise torque from the counterclockwise torque, resulting in a positive net torque of 8.58 N·m. So the correct option is c.

Step-by-step explanation:

The student is asking to calculate the net torque about the pivot on a rod being acted upon by two forces causing opposing torques. To find the net torque, we need to calculate each torque and then subtract the clockwise (cw) torque from the counterclockwise (ccw) torque. Torque (τ) can be calculated using the formula τ = rFsin(θ), where r is the distance from the pivot, F is the force applied, and θ is the angle at which the force is applied relative to the rod.

Step-by-step calculation:


  1. Calculate the torque due to the 7.80 N force acting at 1.60 m from the pivot: τ1 = 7.80 N × 1.60 m × sin(90°) = 12.48 N·m

  2. Calculate the component of the 2.60 N force acting perpendicular to the rod using the sine function: Fperpendicular = 2.60 N × sin(30°) = 1.30 N

  3. Calculate the torque due to this force acting at 3.00 m from the pivot: τ2 = 1.30 N × 3.00 m × sin(90°) = 3.90 N·m

  4. Since the 2.60 N force causes a clockwise (cw) torque, it will have a negative value, so subtract τ2 from τ1 to get the net torque: Net τ = τ1 - τ2 = 12.48 N·m - 3.90 N·m = 8.58 N·m

Since the counterclockwise (ccw) torque is the positive direction, the net torque of 8.58 N·m is positive, giving us option c) 8.58 N·m as the correct answer.

User Damian Dixon
by
6.4k points
1 vote

Answer:

The net torque about the pivot is and the answer is 'c'

c.
T_(net)=8.58

Step-by-step explanation:


T=F*d

The torque is the force apply in a distance so it is the moment so depends on the way to be put it the signs so:


T_1=F_1*d_1


T_1=7.8N*1.6m=12.48N*m


T_2=F_2*d_2


T_2=2.60N**cos(30)*3.0m


T_2= - 3.9 N*m

Now to find the net Torque is the summation of both torques


T_(net)=T_1+T_2


T_(net)=12.48N-3.9N=8.58N

User Sudhir Bastakoti
by
6.3k points