Question

There is a contest being held at Company A. Company A employs forty people. The first 3 employees to correctly complete a riddle each receives an extra vacation day that year. What is the probability that those first 3 employees are in the order of Jack, Bill, and John?

Answer 1

The probability that those first 3 employees are in the order of Jack, Bill, and John is
`(1)/(59280)`

Explanation:

Consider the provided information.

Company A employs forty people. We need to find the probability that those first 3 employees are in the order of Jack, Bill, and John?

First find the total number of ways;

We have 40 employees out of which we need to select only 3.

This can be written as:
`40* 39 * 38=59280`

The number of ways of selecting jack, bill and john in the same order = 1

`Probability=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}`

`Probability=(1)/(59280)`

Therefore, the probability that those first 3 employees are in the order of Jack, Bill, and John is
`(1)/(59280)`.