Question

7.) A syringe initially holds a sample of gas with a volume of 285 mL at 355 K and 1.88 atm. To

what temperature must the gas in the syringe be heated/cooled in order to have a volume of 435
mL at 2.50 atm?
A) 139 K
B) 572 K
C) 175 K
D) 466 K
E) 721 K

Answer 1

T₂ = 721 k

Step-by-step explanation:

Given data:

Initial volume = 285 mL

Initial pressure = 1.88 atm

Initial temperature = 355 K

Final temperature = ?

Final volume = 435 mL

Final pressure = 2.50 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂ T₁ / P₁V₁

T₂ = 2.50 atm × 435 mL × 355 K / 1.88 atm × 285 mL

T₂ = 386062.5 atm. mL. K /535.8 atm. mL

T₂ = 721 k