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Plane microwaves are incident on a thin metal sheet that has a long, narrow slit of width 4.8 cm in it. The microwave radiation strikes the sheet at normal incidence. The first diffraction minimum is observed at θ = 42°. What is the wavelength of the microwaves?

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Answer:


\lambda = 3.21 \ cm

Step-by-step explanation:

given,

width of narrow slit = 4.8 cm

minimum angle of diffraction = θ = 42°

wavelength of the microwave = ?

condition for the diffraction for single slit diffraction


d sin \theta = m \lambda

for the first minima m = 1


d sin \theta = \lambda

wavelength of microwave radiation is equal to


\lambda = d sin \theta


\lambda = 4.8* sin 42^0


\lambda = 3.21 \ cm

the wavelength of microwaves is equal to
\lambda = 3.21 \ cm

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