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What is the equation of the line that passes through the point (-5, -4) and has a

slope of – 3/5?

1 Answer

4 votes

Answer:

y + 4 = -³/₅(x + 5) {the point-slope form of the equation }

y = -³/₅x - 7 {the slope-intercept form of the equation}

3x + 5y = - 35 {standard form of the equation}

Explanation:

The point-slope form of equation is : y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through.

m = -³/₅

(-5, -4) ⇒ x₀ = -5, y₀ = -4

Therefore:

y - (-4) = -³/₅(x - (-5))

y + 4 = -³/₅(x + 5) ← the point-slope form of the equation

y + 4 = -³/₅x - 3 {subtract 4 from both sides}

y = -³/₅x - 7 ← the slope-intercept form of the equation

³/₅x + y = - 7 {multiply both sides by 5}

3x + 5y = - 35 ← standard form of the equation

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