Question

I NEED HELP PLEASE!!

Calculate the amount of heat absorbed when a 15.5-g ice cube melts. The delta Hfus= 6.02 kj/mol.

Answer 1

The amount of heat absorbed is 5.183889 kJ .

Step-by-step explanation:

In conversion of water to ice it rejects some heat while in conversion of ice to water it absorbs heat which is called latent heat which is given as 6.02 kJ/mol.

The amount of ice given is 15.5 g.

Converting it to moles as the latent heat is given in per moles:

`(given\\weight \\ (in\\grams))/(molecular\\weight\\(in\\grams))`

Molecular mass of Hydrogen (H) and Oxygen (O) is 1 u and 16 u respectively.

Molecular mass of water is 18 g (
`H_(2) O` ⇒ 2*1+16=18 ).

mole = 15.5/18 ≈ 0.8611 moles

Therefore the amount of heat absorbed by 15.5 g of ice ( 0.8611 moles) = Latent heat * moles

Heat absorbed = 6.02*0.8611

= 6.02*(15.5/18)

≈ 5.183889 kJ