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Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . What is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas? Be sure your answer has the correct number of significant digits in it.

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Answer:

3.52 grams is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas.

Step-by-step explanation:


CH_4+2O_2\rightarrow CO_2+2H_2O

Moles of methane gas =
(1.28 g)/(16 g/mol)=0.08 mol

Moles of oxygen gas =
(10.1 g)/(32 g/mol)=0.3156 mol

According to reaction 1 moles of methane gas reacts with 2 mole of oxygen gas.

Then 0.08 moles of methane will recast with:


(2)/(1)* 0.08 mol=0.16 mol oxygen gas

As we can see that moles of methane are in limiting amount , so the amount moles of carbon dioxide will depend upon on moles of methane gas.

Limiting reagent = methane

According to reaction , 1 mole of methane gas gives 1 mol of carbon dioxide gas.

Then 0.08 moles of metahjen gas wuill give :


(1)/(1)* 0.08 mol=0.08 mol of carbon dioxide gas.

Mass of 0.08 mople sof carbon dioxde gas :


0.08 mol* 44 g/mol=3.52 g

3.52 grams is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas.

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