Answer:
3.52 grams is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas.
Step-by-step explanation:
![CH_4+2O_2\rightarrow CO_2+2H_2O](https://img.qammunity.org/2020/formulas/chemistry/middle-school/feqlp8ie66t69pnqqwqbu2gnkp0829454u.png)
Moles of methane gas =
![(1.28 g)/(16 g/mol)=0.08 mol](https://img.qammunity.org/2020/formulas/chemistry/college/eknn0maks7qsmnsl5xtvnnmcotnhau5w4s.png)
Moles of oxygen gas =
![(10.1 g)/(32 g/mol)=0.3156 mol](https://img.qammunity.org/2020/formulas/chemistry/college/8b87yo4qwjewr7o296bnsniunk87asnk32.png)
According to reaction 1 moles of methane gas reacts with 2 mole of oxygen gas.
Then 0.08 moles of methane will recast with:
oxygen gas
As we can see that moles of methane are in limiting amount , so the amount moles of carbon dioxide will depend upon on moles of methane gas.
Limiting reagent = methane
According to reaction , 1 mole of methane gas gives 1 mol of carbon dioxide gas.
Then 0.08 moles of metahjen gas wuill give :
of carbon dioxide gas.
Mass of 0.08 mople sof carbon dioxde gas :
![0.08 mol* 44 g/mol=3.52 g](https://img.qammunity.org/2020/formulas/chemistry/college/rg83bo0k7l5dyrl6aophsrovo4z6eaa49u.png)
3.52 grams is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas.