Question

Identify the procedure to determine a formula for self-inductance, or inductance for short. Using the formula derived in the text, find the inductance in henries for a solenoid with 1500 loops of wire wound on a rod 13 cm long with radius 4 cm.

Answer 1

L = 0.109 H

Step-by-step explanation:

Given that,

Number of loops in the solenoid, N = 1500

Radius of the wire, r = 4 cm = 0.04 m

Length of the rod, l = 13 cm = 0.13 m

To find,

Self inductance in the solenoid

Solution,

The expression for the self inductance of the solenoid is given by :

`L=(\mu_o N^2 A)/(l)`

`L=(4\pi * 10^(-7)* (1500)^2* \pi (0.04)^2)/(0.13)`

L = 0.109 H

So, the self inductance of the solenoid is 0.109 henries.