Answer:
L = 0.0319 H
Step-by-step explanation:
Given that,
Number of loops in the solenoid, N = 900
Radius of the wire, r = 3 cm = 0.03 m
Length of the rod, l = 9 cm = 0.09 m
To find,
Self inductance in the solenoid
Solution,
The expression for the self inductance of the solenoid is given by :


L = 0.0319 H
So, the self inductance of the solenoid is 0.0319 henries.