Question

Calculate moles of 3.9g of sodium

Answer 1

`\boxed{\text{0.17 mol}}`

Step-by-step explanation:

`\text{M$_(r)$ of Na} = 22.99\\\text{Moles} = \text{3.9 g } * \frac{\text{1 mol}}{\text{22.99 g}} = \text{0.17 mol}\\\\\text{ The sample contains $\boxed{\textbf{0.17 mol}}$ of Na}`