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If the temperature of a gas is raised from 30°C to 60°C, what happens to the pressure?

1 Answer

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Answer:

The pressure increases by 10% of the original pressure

Thus the new pressure is 1.1 times the original pressure.

Step-by-step explanation:

We are given;

  • Initial temperature as 30°C, but K = °C + 273.15
  • Thus, Initial temperature, T1 =303.15 K
  • Final temperature, T2 is 333.15 K

We are required to state what happens to the pressure;

  • We are going to base our arguments to Pressure law;
  • According to pressure law, the pressure of a gas and its temperature are directly proportional at a constant volume
  • That is; P α T
  • Therefore, at varying pressure and temperature


(P1)/(T1)=(P2)/(T2)

Assuming the initial pressure, P1 is P

Rearranging the formula;

[tex]P2=\frac{P1T2}{T1}[/tex]


P2=((P)(333.15K))/(303.15K)


P2 = 1.099P

= 1.10 P

The new pressure becomes 1.10P

This means the pressure has increased by 10%

We can conclude that, the new pressure will be 1.1 times the original pressure.

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