Question

A flat, rectangular coil consisting of 60 turns measures 23.0 cm by 31.0 cm . It is in a uniform, 1.20-T, magnetic field, with the plane of the coil parallel to the field. In 0.210 s , it is rotated so that the plane of the coil is perpendicular to the field.Part A What is the change in the magnetic flux through the coil due to this rotation?Part B Find the magnitude of the average emf induced in the coil during this rotation.

Answer 1

Answer:25.23 V

Step-by-step explanation:

Given

no of turns
`N=60 turns`

Magnetic Field
`B=1.2 T`

Area of rectangular coil
`A=23* 31=713 cm^2\approx 0.0713m^2`

Change in magnetic Flux is given by

`\Delta \phi =BA\cos \theta`

`\Delta \phi =1.2* 0.0736\cos 0=0.08832 V-s`

(b)Emf induced change in Flux with respect to time and it can be given by

`E=-N\frac{\mathrm{d} \phi }{\mathrm{d} t}`

`E=-60* (0.08832)/(0.21)`

`E=-25.23 V`

The magnitude of emf induced is
`25.23 V`