Question

You start with 12.94 g sample of a mixture containing SiO2, NaCl, and NH4Cl. If after subliming

away the NH4Cl, you have 2.17 grams of sample remaining, what was the mass percent of NH4CI
in the original sample? Show all work.

Answer 1

83.23 %

Step-by-step explanation:

We are given;

• Mass of the sample mixture is 12.94 g
• Mass of the remaining mixture after sublimation is 2.17 g

We are required to get the mass percent of NH₄Cl in the original sample

Step 1 : Calculate mass of NH₄Cl in the original sample;

Mass of NH₄Cl = Total mass of the mixture - remaining mass after sublimation

= 12.94 g - 2.17 g

= 10.77 g

Step 2: Percent by mass of NH₄Cl in the original sample

% of NH₄Cl by mass =(Mass of NH₄Cl÷Total mass of original sample)×100

= (10.77 g ÷ 12.94 g) × 100

= 83.23 %

Therefore, the percent by mass of NH₄Cl in the original sample is 83.23%