Answer:
Bulb will remain at constant brightness for 6 hour
Step-by-step explanation:
We have given resistance of the bulb R = 4 ohm
Potential difference of the battery V = 2 volt
So current
![i=(V)/(R)=(2)/(4)=0.5A](https://img.qammunity.org/2020/formulas/physics/high-school/3oz5utxjfgre0u6mc1dfe7x74hleu8w6d8.png)
Capacity of the battery is given as 3 amp hour
We have to find the time by which bulb will remain at constant brightness
So time will be
![=(3)/(0.5)=6hour](https://img.qammunity.org/2020/formulas/physics/high-school/yf4oe1r1dhgqcyeespcl5vgft260o42hny.png)
So bulb will remain at constant brightness for 6 hour