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Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.) an = 4n cos(7nπ)

User Ezra Chu
by
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1 Answer

9 votes

Answer:

The sequence diverges.

Explanation:

A sequence
a_(n) converges when
\lim_(n \rightarrow \infty) a_(n) is a real number.

In this question, the sequence given is:


a_(n) = 4ncos((7n\pi))

The cosine is always going to be between -1 and 1, so for the convergence of the sequence, we look it as:
a_(n) = 4n. So


\lim_(n \rightarrow \infty) a_(n) = \lim_(n \rightarrow \infty) 4n = \infty

Since the limit is not a real number, the sequence diverges.

User Evgeny Kluev
by
8.2k points
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