Question

What is the factorization of the trinomial below -x^2 + 2x + 48

Answer 1

For this case we must factor the following expression:

`-x ^ 2 + 2x + 48`

We take the sign "-" as a common factor of the expression, taking into account that:

`- * - = +\\- (x ^ 2-2x-48)`

To factor, we must find two numbers that, when multiplied, result in -48 and when added, result in -2. These numbers are -8 and +6.

`-8 + 6 = -2\\(-8) * (+ 6) = - 48`

Then, we factor the expression within the parenthesis as:

`- ((x-8) (x + 6))`

Answer:

`- (x-8) (x + 6)`