Question

Phosphorus will react with oxygen to form diphosphorus pentoxide, P2O5 4P(s)+5O2(g) → 2P2O5(s) How many grams of P2O5 are formed when 4.89 g of P react with excess oxygen?

Answer 1

11.2 g

Step-by-step explanation:

Given,

Mass of P = 4.89 g

Molar mass of
`P` = 30.9738 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (4.89\ g)/(30.9738\ g/mol)`

`Moles_(P)= 0.158\ mol`

According to the reaction shown below as:-

`4P_((s))+5O_2_((g))\rightarrow 2P_2O_5_((s))`

4 moles of P on reaction forms 2 moles of diphosphorus pentoxide

Also,

1 mole of P on reaction forms 2/4 mole of diphosphorus pentoxide

0.158 moles of P on reaction forms
`(2)/(4)* 0.158` moles of diphosphorus pentoxide

Moles of diphosphorus pentoxide = 0.079 moles

Molar mass of diphosphorus pentoxide = 141.9445 g/mol

Mass = Moles * Molar mass = 0.079 moles * 141.9445 g/mol = 11.2 g