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what is the slope of a line perpendicular to the line whose equations is 2x-12y=168. fully reduce your answer

1 Answer

4 votes

Answer:

-6

Explanation:

The equation 2x-12y=168 is in standard form so in order to dtermine the slope you need to convert it to slope-intercept form.

1. subtract 2x from both sides.

-12y=-2x+168

2. divide all terms by -12 (to isolate the y)

y=1/6x-14

3. the equation of a line that is the perpendicular is the opposite and reciprocal of the given slope.

the opposite of 1/6 is -1/6.

The reciprocal of -1/6 is -6/1 OR -6.

-6 is the slope of a line pependicular to 2x-12y=168.

Hope this helps.

User Roelofs
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