Question

Write a balanced equation for its combustion reaction.

C5H12O(l)+6O2(g)→5CO2(g)+6H2O(l) C5H12O(l)+15/2O2(g)→5CO2(g)+6H2O(l) C5H12O(l)+15/2O2(g)→5H2CO3(g)+H2O(l) 2C5H12O(l)+5O2(g)→2C5H12O6(s)

Answer 1

C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)

Step-by-step explanation:

The balanced chemical equation for the combustion of the hydrocarbon in question is;

C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)

• A balanced chemical equation is one in which the number of atoms of each element is equal on both sides of the equation.

• In this case;

• Reactant side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
• Product side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms

• An equation is balanced by putting appropriate coefficients on reactants and products involved in the reaction.
• An equation is balanced so as to obey the law of conservation of mass.