Question

Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speec

up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?
m/s2

Answer 1

The acceleration of the train is 5 m/s².

Step-by-step explanation:

Given:

let the initial velocity of a train = 5 m/s and

final velocity of a train = 45 m/s

time taken = 8 s

To find:

acceleration: ?

Solution:

We define acceleration as change in velocity per unit time that is the difference between the final velocity and initial velocity divided by time.

`Acceleration = \frac{\textrm{final velocity} - \textrm{initial velocity}}{time} \\`

On substituting the above values we get the required acceleration

`Acceleration = (45 - 5)/(8)\\ =(40)/(8)\\ =5\ m/s^(2)`

Therefore,the acceleration of the train is 5 m/s².