Answer:
1/3 is simplified form of given expression.
Explanation:
Given that:
=
![\sqrt[4]{9} \sqrt[2]{9}/ \sqrt[4]{9^5}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6jq36gv7iuh1rake6j32n7lq2vy4ogsy48.png)
Now we will write the radical in simple form first:
=

As bases are same, powers will be added and subtracted as follows:
=

By simplifying the powers:
=

Now denominators are same so numerators can be added
=

For removing the negative sign the base will be inverted:
=

This can be written as follows:
=

i hope it will help you!