Question

A gas evolved during the fermentation of sugar was collected. After purification its volume was found to be 25.0 l at 22.5°c and 702 mmhg. How many moles of gas were collected?

Answer 1

Moles of gas collected = 0.952 mole

Step-by-step explanation:

To calculate the number of moles of the gas collected, we use the equation given by ideal gas which follows:

`PV=nRT`

where,

P = pressure of the gas = 702 mmHg

V = Volume of the gas = 25.0 L

T = Temperature of the gas =
`22.5^oC=[22.5+273.15]K=295.65\ K`

R = Gas constant =
`62.3637\text{ L.mmHg }mol^(-1)K^(-1)`

n = number of moles of gas = ?

Putting values in above equation, we get:

`702\ mmHg* 25.0\ L=n* 62.3637\text{ L.mmHg }mol^(-1)K^(-1)* 295.65\ K\\\\n=(702* 25)/(62.3637* 295.65)\ mol=0.952mol`

Moles of gas collected = 0.952 mole