Question

Amaya ran around 3 times around a 1 mile track in 45 minutes, what was her average velocity for the trip?

Answer 1

Answer: Average Velocity=0, Average speed=4mph

Step-by-step explanation:

Let's begin by stating clear that motiont is the change of position of a body at a certain time. So, during this motion, the Amaya will have a trajectory and a displacement, being both different:

The trajectory is the path followed by Amaya, the distance it travelled (is a scalar quantity).

The displacement is the distance in a straight line between the initial and final position (is a vector quantity).

On the other hand, the velocity is a vector quantity and speed is its magnitude (a scalar quantity).

So, since Amaya ran around a closed track, the distance between her initial position and final position is zero, hence her average velocity is zero
`V_(avg)=0`.

Now, in the case of her average speed
`S_(avg)`, this can be calculated by the following equation:

`S_(avg)=(d)/(t)`

Where:

`d=1(mile)/(track) 3 tracks=3 miles` is the covered distance (the trajectory)

`t=45 min (1 h)/(60 min)=(3)/(4)h=0.75 h` is the time it took to Amaya to cover the mentioned distance

Then:

`S_(avg)=(3 miles)/(0.75 h)`

Finally:

`S_(avg)=4 (miles)/(h)=4 mph`