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The surface of a hill is modeled by z = 100 − 4 x 2 − 2 y 2 . When a group of hikers reach the point (-3,-2,56) it begins to snow. They decide to descend the hill as rapidly as possible. Which of the following vectors points in the direction they should start their descent? < 24 , 8 > < 24 x , 8 y > < − 24 x , − 8 y > < − 24 , − 8 > None of the above

1 Answer

5 votes

Answer:

(-24, -8)

Explanation:

Let us recall that when we have a function f


\large f:\mathbb{R}^2\rightarrow \mathbb{R}\\f(x,y)=z

if the gradient of f at a given point (x,y) exists, then the gradient of f at this point (x,y) gives the direction of maximum rate of increasing and minus the gradient of f at this point gives the direction of maximum rate of decreasing. That is


\large \\abla f=((\partial f)/(\partial x),(\partial f)/(\partial y))

at the point (x,y) gives the direction of maximum rate of increasing


\large -\\abla f

at the point (x,y) gives the direction of maximum rate of decreasing

In this case we have


\large f(x,y)=100-4x^2-2y^2

and we want to find the direction of fastest speed of decreasing at the point (-3,-2)


\large \\abla f(x,y)=(-8x,-4y) \Rightarrow -\\abla f=(8x,4y)

at the point (-3,-2) minus the gradient equals


\large -\\abla f(-3,-2)=(-24,-8)

hence the vector (-24,-8) points in the direction with the greatest rate of decreasing, and they should start their descent in that direction.

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