Question

Using a counter and an if statement inside the while loop, only allow the user five opportunities before ending the program. If the user gets to 5 incorrect inputs, display a message that they have hit the limit of tries and exit the program. (HINT: To completely stop a program use the return command.)

Answer 1

#include <iostream>

using namespace std;

int main ()

{ int cutoff = 5;

int tries = 0;

int u_input = 0;

while (0 == 0)

{ if (tries == cutoff)

{

cout << "You have hit the limit of tries ";

return 0;}

else {

cout << "Enter a postive number";

cin >> u_input;

if (u_input < 0)

{

tries++;

cout << "Not a postive number, Try again !";

}

}

}

return 0;

}

Step-by-step explanation:

create a variable cutoff of type integer for maximum allowed user inputs.

create a variable tries of type integer for number of user inputs.

create a variable u_input of type integer for user inputs.

create an infinite while loop with termination condition 0==0. Inside loop write an if statement where if tries==cutoff return 0 (to terminate program) else ask proceed to ask user for a positive integer number as input.After input check if input number is positive.If input number is positive terminate else increase tries variable value by one ask user to input again