Question

Suppose you start an antique car by exerting a force of 270 N on its crank for 0.275 s. What angular momentum is given to the engine, in kg · m2/s, if the handle of the crank is 0.300 m from the pivot and the force is exerted to create maximum torque the entire time? kg · m2/s

Answer 1

`L_f=22.27\ kg-m^2/s`

Step-by-step explanation:

Given that,

Force exerted on an antique car, F = 270 N

Time, t = 0.275 s

Distance, d = 0.3 m

To find:

The angular momentum given to the engine.

Solution,

We know that the relation between the angular momentum and the torque is given by :

`\tau=(dL)/(dt)`

Since,
`\tau=d* F`

`dF=(dL)/(dt)`

`d.F=(L_f-L_i)/(t)`

`d.F=(L_f)/(t)`

`L_f=d* F* t`

`L_f=0.3\ m* 270\ N* 0.275\ s`

`L_f=22.27\ kg-m^2/s`

So, the angular momentum given to the engine is
`22.27\ kg-m^2/s`.