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Duralin is an alloy of aluminium containing 4.5% manganese, 3.5% copper, and 0.45% magnesium. How much magnesium is present in a 88 g sample of this alloy?

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Answer: The mass of magnesium in given amount of alloy is 0.396 g

Step-by-step explanation:

We are given:

Percent mass of manganese = 4.5 %

Percent mass of copper = 3.5 %

Percent mass of magnesium = 0.45 %

Percent mass of aluminium = (100 - 4.5 - 3.5 - 0.45) = 91.55 %

Mass of alloy = 88 g

We need to calculate the mass of magnesium in 88 g of alloy, we get:


\Rightarrow 88* (0.45)/(100)=0.396g

Hence, the mass of magnesium in given amount of alloy is 0.396 g

User Andrey Usov
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