Question

A ball is thrown vertically upward with an initial velocity of 23.6 meters per second. What is the maximum height reached by the ball? Please include your answer with a unit symbol.

Answer 1

Maximum height attained by the ball will be h = 28.416 m

Step-by-step explanation:

We have given initial speed of the ball u = 23.6 m /sec

At maximum height velocity will be zero so final velocity v = 0 m/sec

Acceleration due to gravity
`g=9.8m/sec^2`

From law of motion we know that
`v^2=u^2-2gh`

`0^2=23.6^2-2* 9.8* h`

h = 28.416 m

So maximum height attained by the ball will be h = 28.416 m