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What is the surface area of a cone that has a radius of 8 feet and a slant height of 12 feet? (Use 3.14 for π.)

301.44 ft 2

502.4 ft 2

200.96 ft 2

803.84 ft 2



1 Answer

2 votes

Answer:


SA=502.4\ ft^2

Explanation:

we know that

The surface area of a cone is equal to


SA=\pi r^(2)+\pi rl

we have


r=8\ ft\\l=12\ ft\\\pi=3.14

substitute the given values


SA=(3.14)(8^(2))+(3.14)(8)(12)


SA=200.96+301.44=502.4\ ft^2

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