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What is the surface area of a cone that has a radius of 8 feet and a slant height of 12 feet? (Use 3.14 for π.)

301.44 ft 2
502.4 ft 2
200.96 ft 2
803.84 ft 2​

2 Answers

5 votes

Answer:

502.4

Explanation:

User Suresh Nagar
by
5.4k points
3 votes

Answer:

Surface area of cone is
502.4\ ft^2

Explanation:

Given:

radius of a cone (r) = 8 feet

slant height of cone (l) = 12 feet

We need to find the surface area of cone.

Total surface area of cone = Area of circle
+ Area of curved surface

Now we know that,

Area of circle =
\pi r^2

Area of curved surface =
\pi rl

Hence Total surface area of cone =
\pi r^2+\pi rl=\pi r(r+l) = 3.14 * 8 (8+12)=3.14*8*20= 502.4 \ ft^2

Surface area of cone is
502.4\ ft^2.

User Max Noel
by
6.1k points