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Find the intensity of a 55 dB sound given I 0=10^-12W/m^2

2.23x10^-6W/m^2
1.01x10^-7W/m^2
3.16x10^-7W/m^2
5.43x10^-6W/m^2

1 Answer

5 votes

Answer:

3.16 ×
10^(-7) W/
m^(2)

Step-by-step explanation:

β(dB)=10 ×
log_(10)((I)/(I_(0) ))


I_(0)=
10^(-12) W/
m^(2)

β=55 dB

Therefore plugging into the equation the values,

55=10
log_(10)(\frac{I}{ [tex]10^(-12)})[/tex]

5.5=
log_(10)(\frac{I}{ [tex]10^(-12)})[/tex]


10^(5.5)=
(I)/(10^(-12) )

316227.76×
10^(-12)= I

I= 3.16 ×
10^(-7) W/
m^(2)

User Alexey Petushkov
by
5.7k points