Question

2. A dog sits 1.5 m from the center of a merry-go-round. The merry-go-round is set in motion, and the dog's tangential speed is 1.5 m/s. What is the dog's centripetal

acceleration?

Answer 1

1.5 m/
`s^(2)` directed towards the center of the circle.

Step-by-step explanation:

Formula for Centripetal Acceleration

`a_(c) =(v^(2) )/(r)`

where v= represents the velocity of the object exhibiting circular motion and r represents the radius in which the body is doing a circular motion.

Given Parameters

v=1.5 m/s

r=1.5 m

Plugging in the values ,

`a_(c) =(1.5^(2) )/(1.5)`

`a_(c)`= 1.5 m/
`s^(2)` directed towards to the center of the circle.