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3 votes
Select the function that matches the graph.

y = 3x
y = 3x2 + 1
y = 3x - 1
y = 3x + 1

User Tumbledown
by
8.6k points

2 Answers

1 vote

Answer:

the first one goes through (0,0) ||||||| the second is an exponential function so it goes through (0,1) and in a u shape going up ||||||| The third goes through (0,-1) ||||||||| The fourth goes through (0,1)

Explanation:

these are identifiein traits so you can find wich one the graph corresponds to since u never gave us a graph.

User Matteo Pagliazzi
by
7.9k points
0 votes

Answer:

The graph is missing, but we can draw and describe each option.

Choice 1


y=3x

This is a linear function which passes throuhg the origin of the coordinate system because it doesn't have the constant
b which is the y-intercept of the line.

The first image attached shows this function.

Choice 2


y=3x^(2) +1

This is a quadratic function. Its graph belongs to a parabola, all quadratic functions are represented by a parabola. In this case, the parabola has a vertex at (0,1). The second image attached shows this function.

Choice 3


y=3x-1

This is also a linear function, which is parallel to the first function, because they have the same slope of 3. But this one has y-intercept at (0,-1). The third image attached shows this function.

Choice 4


y=3x+1

This is also a linear function parallel to function 1 and function 3. The fourth image attached shows its graph. In this case, the line has y-intercept at (0,1).

Select the function that matches the graph. y = 3x y = 3x2 + 1 y = 3x - 1 y = 3x + 1-example-1
Select the function that matches the graph. y = 3x y = 3x2 + 1 y = 3x - 1 y = 3x + 1-example-2
Select the function that matches the graph. y = 3x y = 3x2 + 1 y = 3x - 1 y = 3x + 1-example-3
Select the function that matches the graph. y = 3x y = 3x2 + 1 y = 3x - 1 y = 3x + 1-example-4
User Mstdmstd
by
8.4k points

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