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ASAP I need help with Law of cosines how the heck do you find the degree for #2

ASAP I need help with Law of cosines how the heck do you find the degree for #2-example-1
User Hridya Pv
by
5.4k points

1 Answer

6 votes

Answer:

130.54°

Explanation:

The formula for law of cosines is c^2= a^2+ b^2 -2ab cos(C),

a,b, and c are the sides of the triangle. C is the angle opposite to the side c.

To solve this problem add the given values into the formula, and solve for C.

10^2=5^2+ 6^2- 2(5)(6) cos(C)

100=25+36 - 2(5)(6) cos(C)

100=25+36 -60 cos(C)

100=61 -60 cos(C)

39= -60 cos(C)

cos^-1 (-39/60)= C

130.54°=C

User Denny Sharma
by
5.5k points
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