Answer:
No real roots
Explanation:
The given quadratic equation is
![{x}^(2) + 5x + 7 = 0](https://img.qammunity.org/2020/formulas/mathematics/high-school/jbmgjorr2bbnjfdd85jy7pfvyvigcot14d.png)
Comparing this to the general quadratic equation:
![a {x}^(2) + bx + c = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3i4p36yae7mlnttp9sryr8nhjit0psdlyi.png)
We have a=1, b=5 and c=7
Recall that the discriminant is
![D = {b}^(2) - 4ac](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qk2xzqmx5flelsyuz6n60xhzmz72dcrotq.png)
We plug in the values to get:
![D = {5}^(2) - 4(1)(7)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3hz4kipsnwkojy1d45hy3ourtliqlqic4y.png)
![D =25- 28 = - 3](https://img.qammunity.org/2020/formulas/mathematics/high-school/xc8ubkavv0vp56netx714x6ytc2u4wxvr5.png)
Since the discriminant is less than zero, the given equation has no real roots