Question

URGENT!!-- Please help!

A mixture consists of 45% oxygen, 12% argon, and 43% nitrogen by volume. A sample of this mixture has a pressure of 2.0 atm in a 5.3 L container at 350 K temperature. How many moles of gas are in the container?

Answer 1

Moles of gas = 0.369

Further explanation

Given

P = 2 atm

V = 5.3 L

T = 350 L

Required

moles of gas

Solution

Ideal gas Law

`\tt n=(PV)/(RT)\\\\n=(2* 5.3)/(0.082* 350)\\\\n=0.369`

Avogadro's law : at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles

moles of O₂ = 45% x 0.369 = 0.166

moles of Ar = 12% x 0.369 = 0.044

moles of N = 43% x 0.369 = 0.159