Question

Please help me with this math problem ASAP

Identify the horizontal asymptote of f(x) = quantity 6 x minus 7 over quantity 11 x plus 8.

Answer 1

y = 6/11

Explanation:

If the degrees of the numerator and denominator are equal, the horizontal asymptote is

`y= \frac{\text{leading coefficient of numerator}}{\text{leading coefficient of denominator}}`

The degrees of the numerator and of the denominator in your function are 1 and 1.

The leading coefficients are 6 and 11, so the equation of the horizontal asymptote is

`y = \mathbf{(6)/(11)}`

The diagram below shows the graph of your function with a horizontal asymptote at y = 6/11 ≈ 0.545.