Answer:
x=1+/-4i
Explanation:
(x+1)/3-(2x-1)/x=-1
find the common denominator,
in this case, it's going to be 3x.
(x^2+x)/3x-(6x-3)/3x=-1
(x^2+x-6x+3)/3x=-1
x^2-5x+3=-3x
x^2-5x-(-3x)+3=0
x^2-5x+3x+3=0
x^2-2x+3=0
apply the quadratic formula in order to find the roots for x.
Since ax^2+bx+c=0, in this case,
a=1, b=-2, c=3
--------------------------
x=(-b+/-sqrt(b^2-4ac))/2a
x=(2+/-sqrt(4-12))/2
x=(2+/-8i)/2
x=1+/-4i