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Direct variations need help

Direct variations need help-example-1

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Answer:

Part 11) The table represent a direct variation. The equation is
y=18x

Part 12) The table represent a direct variation. The equation is
y=0.4x

Explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
y/x=k or
y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Part 11)

For x=0.5, y=9

Find the value of k


k=y/x ----->
k=9/0.5=18

For x=3, y=54

Find the value of k


k=y/x ----->
k=54/3=18

For x=-2, y=-36

Find the value of k


k=y/x ----->
k=-36/-2=18

For x=1, y=18

Find the value of k


k=y/x ----->
k=18/1=18

For x=-8, y=-144

Find the value of k


k=y/x ----->
k=-144/-8=18

The values of k is the same for each ordered pair

therefore

The table represent a direct variation

The linear equation is


y=18x

Part 12)

For x=-5, y=-2

Find the value of k


k=y/x ----->
k=-2/-5=2/5=0.40

For x=3, y=1.2

Find the value of k


k=y/x ----->
k=1.2/3=0.40

For x=-2, y=-0.8

Find the value of k


k=y/x ----->
k=-0.8/-2=0.4

For x=10, y=4

Find the value of k


k=y/x ----->
k=4/10=0.4

For x=20, y=8

Find the value of k


k=y/x ----->
k=8/20=0.4

The values of k is the same for each ordered pair

therefore

The table represent a direct variation

The linear equation is


y=0.4x

User Arvidj
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