Question

Calculate the volume in liters of a 3.2*10^-5 M silver(II) oxide solution that contains of silver(II) oxide . Round your answer to significant digits.

Answer 1

The complete question is as follows:

Calculate the volume in liters of a
`3.2 * 10^(-5) M` silver(II) oxide solution that contains 200 g of silver(II) oxide . Round your answer to significant digits.

Step-by-step explanation:

Given: Molarity =
`3.2 * 10^(-5) M`, mass = 200 g

The number of moles is given mass divided by molar mass of substance.

Molar mass of silver(II) oxide
`(Ag_(2)O)` is 231.735 g/mol. Hence,

No. of moles =
`(mass)/(molar mass)`

=
`(200 g)/(231.735 g/mol)`

= 0.863 moles

Molarity is the number of moles present in liter of solution. Therefore,

Molarity =
`(no. of moles)/(Volume (in L))`

So, volume (in L) =
`(no. of moles)/(molarity)`

=
`(0.863 mol)/(3.2 * 10^(-5)M)`

=
`0.269 * 10^(5)` L

Thus, volume of given solution is
`0.269 * 10^(5)` L.