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Write the expression 2a+b in the form of a fraction with the given denominator. Check if the domain of the expression changed. If yes, state the changes explicitely.

3a

User Xref
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Answer:

See below

Explanation:

I will assume the given denominator is 3a as there is nothing attached to the statement.

Lets first look at the domain of 2a+b. As it is a polynomial with unknowns a and b, we know it has its domain in all real numbers for both a and b as every polynomial does. For verifying it replace a and b by any real number you can think of.

Domain = a, b belonging to R

Now, if we divide 2a+b by 3a we will have:

(2a+b)/3a

As know we don not have a polynomial we cant state that the domain will still be all the real numbers for sure. We need to go further.

We have a fraction and as every fraction the denominator CAN'T be equal to 0, so 3a MUST be different to 0. This means that a MUST be different to 0. So, now our domain changes:

domain' = a, b belonging to R and a different to 0.

User Vishal Ghosh
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