Question

a force 10N drags a mass 10 kg on a horizontal table with acceleration 0.2m\s. If the acceleration due to gravity is 10m\s2, a coefficient of friction between the moving mass and a table is?​

Answer 1

Explanation: 0.02

Recall: μ mg = ma

μ = ?

m = 10N

g = 10m\s2

a = 0.2m\s

Substituting the values , we have

μ x 10 x 10 = 10 x 0.2

100 μ = 2

μ = 2/100

μ = 1/50

μ = 0.02

μ = 0.02