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-3+9x>87 or -x-9>-17​

User Mikegrb
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1 Answer

3 votes

Answer:


\large\boxed{x\in(-\infty,\ 8)\ \cup\ (10,\ \infty)}

Explanation:


-3+9x>87\qquad\text{add 3 to both sides}\\\\9x>90\qquad\text{divide both sides by 9}\\\\\boxed{x>10}\to(1)\\\\-x-9>-17\qquad\text{add 9 to both sides}\\\\-x>-8\qquad\text{change the signs}\\\\\boxed{x<8}\to(2)\\\\\text{From (1) and (2) we have:}\\\\x>10\ or\ x<8\to x\in(-\infty,\ 8)\ \cup\ (10,\ \infty)

-3+9x>87 or -x-9>-17​-example-1
User Ingeniarius
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