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38 votes
38 votes
Evaluate (10 – 4i) ÷ (5 + i).

Fifty-four twelfths minus fifteen twelfths i
Twenty-three twelfths minus fifteen twelfths i
Fifty-four thirteenths minus fifteen thirteenths i
Twenty-three thirteenths minus fifteen thirteenths i

User Sharpneli
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2 Answers

16 votes
16 votes

Final answer:

To solve (10 - 4i) ÷ (5 + i), we multiply by the conjugate of the denominator. The result is (54 - 30i)/26, which simplifies to Twenty-three thirteenths minus fifteen thirteenths i.

Step-by-step explanation:

To evaluate the complex number division (10 − 4i) ÷ (5 + i), we should multiply the numerator and denominator by the conjugate of the denominator to remove the imaginary part from the denominator. The conjugate of (5 + i) is (5 - i). So we do the following:

(10 - 4i) * (5 - i)
---------------------
(5 + i) * (5 - i)

Now let's multiply the complex numbers:

(10 * 5 + 10 * -i - 4i * 5 + 4i * i)
-----------------------------------
(5^2 - i^2)

When we simplify:

(50 - 10i - 20i - 4(-1))
-----------------------
(25 + 1)

This simplifies further to:

(54 - 30i)
------------
26

Finally, we divide each term by the denominator:

54/26 - 30i/26

The result is reduced to:

Twenty-three thirteenths minus fifteen thirteenths i.

The correct answer among the options given is therefore Twenty-three thirteenths minus fifteen thirteenths i.

User Woloski
by
2.8k points
10 votes
10 votes

Answer: D
(23)/(13) - (15)/(13) i

Step-by-step explanation:

User Crickeys
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2.8k points