Question

Ind.

Independent Practice
Use any method you choose to solve the equation.
mula
Use an.
3x+2x-4=0
(
A.
A. -0.87, -1.54
-0.87. -16
and
O
B.
-0.87. 1.54
C. 0.87, 1.54
D. 0.87,-1.54

Answer 1

`x=-(1-√(13) )/(3) ,-(1+√(13) )/(3)`

`0.87, -1.54`

Explanation:

`3x^2+2x-4=0`

Use the quadratic formula:

`x=(-b+√(b^2-4ac) )/(2a) ,(-b-√(b^2-4ac) )/(2a)`

`x=(-2+√(2^2-4*3*-4) )/(2*3) ,(-2-√(2^2-4*3*-4) )/(2*3)`

Simplify:

`x=(-2+2√(13) )/(6) ,(-2-2√(13) )/(6)`

`x=-(1-√(13) )/(3) ,-(1+√(13) )/(3)`

Answer 2

D. 0.87, -1.54

Explanation:

The easiest method I know is to let a graphing calculator show you the solutions. The graph shows solutions to be approximately -1.54 and 0.87.