Question

A car with an initial velocity of O m/s and a mass of 1500 kg reaches a velocity of 15 m/s in 5

seconds. What is the acceleration of the car? How much net force was required to reach
this acceleration?​

Answer 1

Answer:the answer can be find out by the following steps;

Step-by-step explanation:

Answer 2

The acceleration of the car is
`3 m / s^(2)`. And the force required to reach the acceleration is 4500 N.

Step-by-step explanation:

Equations of Motion describe different relations between motion parameters. One of them is,

`v_(f)=v_(i)+a t`

And,
`F=m * a` , from Newton’s laws

So, given,

Initial velocity of the car
`v_(i)` = 0

Mass of the car, m = 1500 kg

Velocity acquired
`v_(f)` = 15 m/s

Time taken to acquire velocity t = 5 seconds.

Now, since
`v_(f)=v_(i)+a t`, To find the acceleration, rearrange the above equation, we get as follows,

`a=(\left(v_(f)-v_(i)\right))/(t)`

Then, by applying the given data in above equation, we get

`a=((15-0))/(5)=(15)/(5)=3 m / s^(2)`

Now, find the force to reach
`3 m / s^(2)` acceleration as follows,

`F=m * a=1500 * 3=4500 N`