Question

A wagon, initially traveling at a constant 8.2 m/s, starts going down a hill that creates an acceleration of 9.0 m/s2. What is the wagon's velocity 6.6 s after it starts accelerating down the hill?

Answer 1

67.6m/s

Step-by-step explanation:

Given parameters:

Initial velocity = 8.2m/s

Acceleration = 9.0m/s²

Time = 6.6s

Unknown:

Final velocity = ?

Solution:

To solve this problem, we use the expression below:

Acceleration =
`(v - u )/(t)`

v is the final velocity

u is the initial velocity

t is the time taken

9 =
`(v - 8.2)/(6.6)`

v - 8.2 = 59.4

v = 59.4 + 8.2 = 67.6m/s