Final answer:
To heat a 500.0-gram iron skillet by 0.95°C, 213.775 joules of heat must be absorbed, using the specific heat capacity of iron and the given formula for heat energy.
Step-by-step explanation:
To calculate the amount of heat (q) required to raise the temperature of an iron skillet, we use the formula q = mcΔT, where m is the mass of the skillet, c is the specific heat capacity of iron, and ΔT is the change in temperature. For our problem:
q = (500.0 g) × (0.449 J/g°C) × (0.95°C)
Carrying out the multiplication:
q = 213.775 J
Therefore, 213.775 joules of heat must be absorbed to raise the skillet's temperature by 0.95°C.
The heat absorbed to raise the temperature of an iron skillet can be calculated using the equation Q = msΔT.
Q represents the heat, m is the mass of the skillet, s is the specific heat of iron, and ΔT is the change in temperature.
Plugging in the values, Q = (500.0 g)(0.449 J/g °C)(0.95 °C) = 213.61 J.