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X^(logx) = 1000000x
Find x.

User RashFlash
by
5.2k points

1 Answer

7 votes

Answer:


x = 1000 or
x = 0.01

Explanation:

We are given a logarithmic equation of x and we have to solve it for x.

Given,


x^(\log x) = 1000000x


x^(\log x) = 10^(6) * x

Now, taking log on both sides, we get


\log x^(\log x) = \log 10^(6) * x


\log x .\log x = \log 10^(6)  + \log x

{Since
\log a^(b) = b\log a and
\log ab = \log a + \log b}


(\log x)^(2) = 6 + \log x

{Since log 10 = 1}

a² = 6 + a {Where, a = log x}

⇒ a² - a - 6 = 0

⇒ (a - 3)(a + 2) = 0

a = 3 or a = -2


\log x = 3 or
\log x = - 2

Now, converting logarithm to exponential form, we get,


x = 10^(3) = 1000 or
x = 10^(- 2) = (1)/(100) = 0.01 (Answer)

User Petr Krampl
by
5.9k points